matlab序列移位函数(关于matlab中函数的移位!!在线等)

本文目录
- 关于matlab中函数的移位!!在线等
- matlab 问题
- matlab中的位函数bitshift(A,k,n)如何使用
- matlab移位函数的应用
- 解疑 MATLAB循环移位
- matlab编程中的序列翻转移位指令
关于matlab中函数的移位!!在线等
x1=-10:0.1:10;
y1=raylpdf(x1+4.8,4.8);
x2=-10:0.1:10;
y2=normpdf(x2,0,3.16);
figure
plot(x1,y1,x2,y2)
matlab 问题
clear all;
clc;
I1=imread(’D:\ebook\ref.bmp’);
I2=imread(’D:\ebook\swt.bmp’);
unregistered =I2;%%未配准图像
rect=I1;%%参考图像
cpselect(unregistered(:,:,1),rect);%%%选择点对,选完后记得保存
uiwait(msgbox(’Click OK after closing the CPSELECT window.’,’Waiting...’))
input_points_corr= cpcorr(input_points,base_points,unregistered,rect);
tform = cp2tform(input_points_corr,base_points,’linear conformal’);%%仿射变换
registered = imtransform(unregistered,tform,’XData’,[1 300], ’YData’,[1 300]);%%对图像进行重采样
H.Position=[232 258 600 402];
figure(H)
subplot(2,2,1)
imagesc(rect)
title(’Original image 1’)
subplot(2,2,3)
imagesc(unregistered)
title(’Unmatched image 2’)
subplot(2,2,2)
imagesc(rect)
title(’Original image 1’)
subplot(2,2,4)
imagesc(registered)
title(’Matched image 2’)
colormap (gray)
步骤:
1 运行程序,在input里点一个点,在base里在大概相等的位置点一个点,这个两个点构成点对;
2 选取三对以上的点(仿射变换,至少需要三对点);
3 选完后,点file -save points to workspace ,然后再点击ok按钮;
这函数不是很好,你选取的点对位置差不多的话,配准较好,差的远的话,配准会失效;
matlab中的位函数bitshift(A,k,n)如何使用
k是移位的位数,n是有用位数!
clc;
a=[1 3 5 7];
a1=bitshift(a,3)
dec2bin(a1)
a2=bitshift(a,3,1)
dec2bin(a2)
a2=bitshift(a,3,2)
dec2bin(a2)
a2=bitshift(a,3,3)
dec2bin(a2)
a2=bitshift(a,3,4)
dec2bin(a2)
a2=bitshift(a,3,5)
dec2bi
Matlab的两种移位运算:
1) circshift 矩阵移位
circshift :Shift array circularly
Syntax : B = circshift(A,shiftsize)
Description :
B = circshift(A,shiftsize) circularly shifts the values in the array, A, by shiftsize elements. shiftsize is a vector of integer scalars where the n-th element specifies the shift amount for the n-th dimension of array A. If an element in shiftsize is positive, the values of A are shifted down (or to the right). If it is negative, the values of A are shifted up (or to the left). If it is 0, the values in that dimension are not shifted.
Example :
Circularly shift first dimension values down by 1.
A = [ 1 2 3;4 5 6; 7 8 9]
A =
1 2 3
4 5 6
7 8 9
B = circshift(A,1)
B =
7 8 9
1 2 3
4 5 6
Circularly shift first dimension values down by 1 and second dimension values to the left by 1.
B = circshift(A,[1 -1]);
B =
8 9 7
2 3 1
5 6 4
2)bitshift 位移位
bitshift :
Shift bits specified number of places
Syntax :
C = bitshift(A, k)
C = bitshift(A, k, n)
Description :
C = bitshift(A, k) returns the value of A shifted by k bits. Input argument A must be an unsigned integer or an array of unsigned integers. Shifting by k is the same as multiplication by 2^k. Negative values of k are allowed and this corresponds to shifting to the right, or dividing by 2^abs(k) and truncating to an integer. If the shift causes C to overflow the number of bits in the unsigned integer class of A, then the overflowing bits are dropped.
C = bitshift(A, k, n) causes any bits that overflow n bits to be dropped. The value of n must be less than or equal to the length in bits of the unsigned integer class of A (e.g., n 《= 32 for uint32).
Instead of using bitshift(A, k, 8) or another power of 2 for n, consider using bitshift(uint8(A), k) or the appropriate unsigned integer class for A.
Examples:
Example 1
Shifting 1100 (12, decimal) to the left two bits yields 110000 (48, decimal).
C = bitshift(12, 2)
C =
48
Example 2
Repeatedly shift the bits of an unsigned 16 bit value to the left until all the nonzero bits overflow. Track the progress in binary:
a = intmax(’uint16’);
disp(sprintf( ...
’Initial uint16 value %5d is %16s in binary’, ...
a, dec2bin(a)))
for k = 1:16
a = bitshift(a, 1);
disp(sprintf( ...
’Shifted uint16 value %5d is %16s in binary’,...
a, dec2bin(a)))
end
n(a2)
matlab移位函数的应用
你向量n的长度和向量x的长度不一样啊,
x=[zeros(1,2)
x2];等于你在原来x2元素前面添加了两个0
n还是原来的长度,
stem(n,x)肯定不能运行出来啊
解疑 MATLAB循环移位
可以直接使用MATLAB自带的函数circshift:
circshift(a,[0,-3])
它的意思是将a的行不换,a的前3列置后
a=1:10;b=circshift(a,[0,-3])
b =
4 5 6 7 8 9 10 1 2 3
matlab编程中的序列翻转移位指令
circshift(a,[n1,n2])循环移位函数,自己看帮助。
至于翻转自己编吧,挺简单的,比如:第一个为循环移位,第二个为翻转
a =
1 2 3 4 5 6 7
》》 circshift(a,[0,2])
ans =
6 7 1 2 3 4 5
for i=1:length(a)
b(i)=a(length(a)-i+1);
end
b =
7 6 5 4 3 2 1
希望有帮助,纯手打,现编的,试试吧。

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